Answer
See graph.
domain $(-\infty,\infty)$, range $(1,\infty)$, H.A. $y=1$.
Work Step by Step
Step 1. To obtain the graph of $f(x)=2^x+1$ from $y=2^x$, shift the curve 1 unit up. See graph.
Step 2. We can determine the domain $(-\infty,\infty)$, range $(1,\infty)$, horizontal asymptote H.A. $y=1$.
