Answer
(a) $ -26$.
(b) $ -241$.
(c) $ 16$.
(d) $ -1$.
Work Step by Step
Given $f(x)=3x-5$ and $g(x)=1-2x^2$, we have:
(a) $(f\circ g)(2)=f(1-2(2)^2)=f(-7)=3(-7)-5=-26$.
(b) $(g\circ f)(-2)=g(3(-2)-5)=g(-11)=1-2(-11)^2=-241$.
(c) $(f\circ f)(4)=f(3(4)-5)=f(7)=3(7)-5=16$.
(d) $(g\circ g)(-1)=g(1-2(-1)^2)=g(-1)=1-2(-1)^2=-1$.
