Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 3 - Polynomial and Rational Functions - Section 3.6 Polynomial and Rational Inequalities - 3.6 Assess Your Understanding - Page 265: 89

Answer

$y=\frac{2}{3} \sqrt{x}$

Work Step by Step

$y$ varies directly with $\sqrt{x}$ so the equation that represents the variation is of the form $y=k\sqrt{x}$ where $k$ is the constant of variation. Given that $y=2$ when $x=9$, substituting these values into the equation above gives: \begin{array}{l} 2=k \sqrt{9} \\ 2=k \times 3 \\ k=\frac{2}{3} \end{array} Substitute $k=\frac{2}{3}$ in the equation to obtain $y=\frac{2}{3} \sqrt{x}$.
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