Answer
$y=\frac{x^2}{(x+2)(x-2)}$
Work Step by Step
Step 1. Identify asymptote(s): V.A. $x=\pm2$, H.A. $y=1$,
Step 2. Write a general form $y=\frac{x^2+a}{(x+2)(x-2)}$,
Step 3. Use point $(0,0)$, we have $a=0$,
Step 4. Provide one solution $y=\frac{x^2}{(x+2)(x-2)}$
