Answer
$(-3,11)$, $(2,-4)$.
Work Step by Step
Step 1. Let $f(x)=g(x)$, we have $x^2-2x-4=-3x+2 \Longrightarrow x^2+x-6=0 \Longrightarrow (x+3)(x-2)=0 \Longrightarrow x=-3, 2$.
Step 2. $f(-3)=-3(-3)+2=11$ giving point $(-3,11)$.
Step 3. $f(2)=-3(2)+2=-4$ giving point $(2,-4)$.
