Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 3 - Polynomial and Rational Functions - Section 3.3 Complex Zeros; Fundamental Theorem of Algebra - 3.3 Assess Your Understanding - Page 232: 50



Work Step by Step

The given equation is: $\sqrt{3-x}=5$ On squaring both sides of the equation, we obtain: $(\sqrt{3-x})^2=5^2$ $3-x=5^2 \implies 3-x=25$ or, $3-x-3=25-3 \implies -x=22$ Thus, we have: $x=-22$
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