## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$x=-22$
The given equation is: $\sqrt{3-x}=5$ On squaring both sides of the equation, we obtain: $(\sqrt{3-x})^2=5^2$ $3-x=5^2 \implies 3-x=25$ or, $3-x-3=25-3 \implies -x=22$ Thus, we have: $x=-22$