## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Sum: $3i$ Product: $1+21i$
The sum of complex numbers can be expressed as: $(a+bi)+(c+di)=(a+c)+\ i (b+d)$ Now, the required sum is: $(3-2i)+(-3+5i)=[3+(-3)]+\ i (-2+5)=3i$ The product of complex numbers can be expressed as: $(a+bi)\cdot(c+di)=ac+adi+bci-bd=(ac-bd)+\ i (bc+ad)$ Now, the required product is: $(3-2i)(-3+5i)=3(-3)+3(5)i+(-2)i(-3)-(-2)5=-9+15i+6i+10=1+21i$