Chapter 3 - Polynomial and Rational Functions - Section 3.2 The Real Zeros of a Polynomial Function - 3.2 Assess Your Understanding - Page 226: 126

x-intercept : $ x=4$ y-intercepts: $y=\sqrt {12}, -\sqrt {12}$

Our aim is to simplify the equation $3x+y^2=12$ and then compute the $x$ and $y$ intercepts. We find the x-intercept by letting $y=0$ $3x +(0)^2=12 \\3x=12 \\ x=4$ To find the y-intercepts, we let $x=0$ $3(0)+y^2=12 \\y^2=12 \\ y=\sqrt {12}, -\sqrt {12}$