Answer
(a) $x=-3,2$.
(b) $x=-6,-1$.
Work Step by Step
(a) Given $G(x)=(x+3)^2(x-2)$, we can identify the x-intercept(s) as $x=-3,2$.
(b) As $y=G(x+3)$ can be obtained from $y=G(x)$ by shifting the curve 3 units to the left, the new x-intercepts are $x=-6,-1$.
