Answer
$y=-\frac{1}{4}(x+1)^2(x-1)(x-4)$.
Work Step by Step
Step 1. Find zeros $x=1,4$ (multiplicity 1), $x=-1$ (multiplicity 2).
Step 2. Write a general form $y=a(x+1)^2(x-1)(x-4)$.
Step 3. Use point $(3,8)$, $8=a(3+1)^2(3-1)(3-4)$, we have $a=-\frac{1}{4}$
Step 4. Provide the answer $y=-\frac{1}{4}(x+1)^2(x-1)(x-4)$.