Answer
$(\pm2,0),(0,9)$
Work Step by Step
Step 1. For x-intercept(s), let $y=0$, we have $x^2=4, x=\pm2$ or $(\pm2,0)$
Step 2. For y-intercept(s), let $x=0$, we have $4y=36, y=9$ or $(0,9)$
Step 3. Thus we have $(\pm2,0),(0,9)$
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