Answer
center $(5,-2)$, radius $r=3$.
Work Step by Step
$x^2-10x+y^2+4y=-20 \longrightarrow x^2-10x+25+y^2+4y+4=-20+25+4 \longrightarrow (x-5)^2+(y+2)^2=9$. Thus we have the center $(5,-2)$, radius $r=3$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.4 Properties of Quadratic Functions - 2.4 Assess Your Understanding - Page 160: 103
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