Answer
(a) not on the graph.
(b) $f(-2) =-1$, $(-2,-1)$.
(c) $x=-8$, $(-8,2)$.
Work Step by Step
Given $f(x)=\frac{x}{x+4}$, we have:
(a) $f(1)=\frac{1}{1+4}=\frac{1}{5}\ne\frac{1}{4}$, thus the point is not on the graph.
(b) $f(-2)=\frac{-2}{-2+4}=-1$, and the point is $(-2,-1)$.
(c) $f(x)=\frac{x}{x+4}=2\Longrightarrow 2x+8=x \Longrightarrow x=-8$, and the point is $(-8,2)$.
