Answer
$$\approx 23.66~units^2$$
Work Step by Step
To find the area of the triangle, we will consider Heron's theorem as follows:
$$K=\sqrt{s(s-a)(s-b)(s-c)} ...(1)$$
where $s=\dfrac{a+b+c}{2}$
We are given the three sides of length 6, 9, and 13. Thus, we have:
$$s=\dfrac{6+9+13}{2}=14 $$
Now, equation (1) becomes:
$$K=\sqrt{14(14-6)(14-9)(14-13)} \approx 23.66~units^2$$