Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.4 The Tangent Problem; The Derivative - 13.4 Assess Your Understanding - Page 918: 54

Answer

$$\approx 23.66~units^2$$

Work Step by Step

To find the area of the triangle, we will consider Heron's theorem as follows: $$K=\sqrt{s(s-a)(s-b)(s-c)} ...(1)$$ where $s=\dfrac{a+b+c}{2}$ We are given the three sides of length 6, 9, and 13. Thus, we have: $$s=\dfrac{6+9+13}{2}=14 $$ Now, equation (1) becomes: $$K=\sqrt{14(14-6)(14-9)(14-13)} \approx 23.66~units^2$$
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