Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.4 The Tangent Problem; The Derivative - 13.4 Assess Your Understanding - Page 916: 8

Answer

True

Work Step by Step

Let $s(t)$ be the position function of the particle. The velocity of the particle can be defined as the rate of change of the position function and can be written as: $v(t)=\dfrac{d (s(t))}{dt}$. or, $v(t)=s'(t)$ The $s'(t)$ is the instantaneous velocity of the position function. So, the given statement is True.
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