Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.3 One-sided Limits; Continuous Functions - 13.3 Assess Your Understanding - Page 910: 93

Answer

$ ln(\frac{x^5y^2}{z^4})$

Work Step by Step

$5ln(x)+2ln(y)-4ln(z)=ln(x^5)+ln(y^2)-ln(z^4)=ln(\frac{x^5y^2}{z^4})$
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