Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.3 One-sided Limits; Continuous Functions - 13.3 Assess Your Understanding - Page 909: 37

Answer

$1$

Work Step by Step

We find the right-hand limit as follows: $\lim\limits_{x \to \frac{\pi}{2}^{+}} f(x)=\lim\limits_{x \to \frac{\pi}{2}^{+}} \sin (x) \\=\sin (\dfrac{\pi}{2}) \\=1$
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