Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Test - Page 928: 17


$\dfrac{106}{3} \ ft/second$ or, $ 35.333 \ ft/second$

Work Step by Step

The general formula for the average rate of change of distance (S) from $t=3 \ seconds $ to $t=6 \ seconds$ is: $\dfrac{f(y)-f(x)}{y-x}$ Here, we have: $\dfrac{\triangle s}{\triangle t}=\dfrac{S(6)-S(3)}{6-3}$ or, $=\dfrac{137-31}{3}$ or, $=\dfrac{106}{3}$ or, $=35.333 \ ft/second$
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