Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.3 Probability - 12.3 Assess Your Understanding - Page 887: 75

Answer

$(-3,3\sqrt 3)$

Work Step by Step

Use the given polar coordinates, we have $x=6cos\frac{2\pi}{3}=-3$ and $y=6sin\frac{2\pi}{3}=3\sqrt 3$, thus the rectangular coordinates are $(-3,3\sqrt 3)$
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