Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 876: 54

Answer

(a) $3003$ (b) $ 20475$ (c) $ 16653$

Work Step by Step

(a) Use the combination formula, we have $C(15,5)=3003$ (b) $C(15,3)C(10,2)=20475$ (c) $C(15,5)+C(15,4)C(10,1)=3003+(1365)(10)=16653$
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