Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 874: 5

Answer

$\dfrac{n!}{(n-k)!}$

Work Step by Step

If we want to arrange $k$ elements out of $n$ where order matters (which is called permutation), not allowing repetition, we can do this in $P(n, k)=\dfrac{n!}{(n-k)!}$ different ways.
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