#### Answer

$\dfrac{n!}{(n-k)!}$

#### Work Step by Step

If we want to arrange $k$ elements out of $n$ where order matters (which is called permutation), not allowing repetition, we can do this in $P(n, k)=\dfrac{n!}{(n-k)!}$ different ways.

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Published by
Pearson

ISBN 10:
0-32193-104-1

ISBN 13:
978-0-32193-104-7

$\dfrac{n!}{(n-k)!}$

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