#### Answer

$80,000$ different 5-digit numbers numbers

#### Work Step by Step

There are 8 selections for first choice ( because 0 and 1 are excluded), and 10 selections each for the second, third, fourth and fifth choices.
Using multiplication principle of counting, the number of 5-digit numbers that can be formed with the given restrictions is:
$= 8\times10\times10\times10\times10
\\= 80,000$.