Answer
$336$
Work Step by Step
If we want to choose $k$ elements out of $n$ with regard to order and not allowing repetition, we use permutations:
$_{n}P_k=\frac{n!}{(n-k)!}$
Hence, we have:
$_{8}P_3=\frac{8!}{(8-3)!}=8\cdot7\cdot6=336$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 12 - Counting and Probability - Chapter Review - Review Exercises - Page 888: 10
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