Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.5 The Binomial Theorem - 11.5 Assess Your Understanding - Page 857: 16

Answer

$17,672, 631,900\approx 1.7673\times 10^{10}$

Work Step by Step

According to the binomial theorem, we have: $\displaystyle{n\choose k}=\dfrac{n!}{(n-k)! \ k!}$. Where $0!=1$ Substitute $37$ for $n$ and $19$ for $k$ in the above formula. Therefore, $\dbinom{37}{19}=\dfrac{37!}{19! \ (37-19)!} \\ =\dfrac{37!}{19! \ 18!}$ Now, we will use a calculator to find the result. $\dfrac{37!}{19! \ 18!}=17,672, 631,900$
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