Answer
See below.
Work Step by Step
1. Test for $n=1$, we have $1^2-1+2=2$ is divisible by 2, thus it is true.
2. Assume the statement is true for $n=k$, we have
$k^2-k+2=2$ is divisible by 2
3. For $n=k+1$, we have $(k+1)^2-(k+1)+2=k^2+2k+1-k-1+2=(k^2-k+2)+2k$ which contains two part and both are divisible by 2, thus it is true for $n=k+1$
4. We conclude that the statement is true for any $n$.