Answer
$\frac{x^2}{4}-\frac{y^2}{12}=1$
Work Step by Step
1. The center is at $(0,0)$ (midpoint of vertices) with a horizontal transverse axis,
2. $a=2, c=4$, thus $b^2=c^2-a^2=12$
3. The equation is $\frac{x^2}{4}-\frac{y^2}{12}=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.3 Geometric Sequences; Geometric Series - 11.3 Assess Your Understanding - Page 847: 113
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