Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.3 Geometric Sequences; Geometric Series - 11.3 Assess Your Understanding - Page 845: 86

Answer

$\$ 6655.58$

Work Step by Step

Since, the price decreases by $ 15\%$ and $15\%=0.15$, then we will multiply $1-0.15=0.85$ to the present value or term to get the value of the equipment the following year. We know that $a_{1}=15,000$ $\\a_{2}=15,000(0.85)\\ a_{3}=15,000(0.85)^{2}$ and so on. This shows a geometric sequence with $a_{1}=15,000$, $r=0.85$ Hence, the $n^{th}$ term of the geometric sequence is given by the formula $a_n=a_1r^{n-1} =15000(0.85)^{n-1}$ We need to find $a_5$. Using the formula above gives: $a_{5}=15,000(0.85)^{5-1}=15000(0.85^4)\approx \$ 6655.58$
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