## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$f(2)=\dfrac{1}{2}$ $f(3)=\dfrac{2}{3}$
To get $f(2)$ substitute in $x=2$ into the function: $f(2)=\dfrac{2-1}{2}=\dfrac{1}{2}$ Similarly for $f(3)$: $f(3)=\dfrac{3-1}{3}=\dfrac{2}{3}$