Answer
$-\frac{1}{32}, 1$
Work Step by Step
Let $u=m^{1/5}$, we have $2u^2-u-1=0$ or $(2u+1)(u-1)=0$, thus $u=-\frac{1}{2}, 1$ and $m=u^5=-\frac{1}{32}, 1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 10 - Systems of Equations and Inequalities - Section 10.8 Linear Programming - 10.8 Assess Your Understanding - Page 812: 33
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