Answer
$\begin{cases}x\ge0 \\ x\le5 \\ y\le6 \\ 2x-y\le8 \\ 3x+4y\ge12 \end{cases}$
Work Step by Step
Based on the given graph, we can identify the equation for the 1st red line as $y=(\frac{2-0}{5-4})(x-4)$ or $2x-y=8$,
we can identify the equation for the 2nd red line as
$y-3=(\frac{3-0}{0-4})(x)$ or $3x+4y=12$,
thus the inequalities
$\begin{cases}x\ge0 \\ x\le5 \\ y\le6 \\ 2x-y\le8 \\ 3x+4y\ge12 \end{cases}$
