Answer
$\begin{cases}x\ge0 \\ y\ge0 \\ x\le4 \\ x+y\le6 \end{cases}$
Work Step by Step
Based on the given graph, we can identify the equation for the red line as
$y-6=(\frac{6-2}{0-4})x$ or $x+y=6$
thus the inequalities
$\begin{cases}x\ge0 \\ y\ge0 \\ x\le4 \\ x+y\le6 \end{cases}$
