Answer
See graph
Work Step by Step
See graph for $f(x)=\frac{2x^2-x-1}{x^2+2x+1}=\frac{(2x+1)(x-1)}{(x+1)^2}$. We have: V.A. $x=-1$, H.A. $y=2$, x-intercept(s) $x=-\frac{1}{2},1$, y-intercept $y=-1$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 10 - Systems of Equations and Inequalities - Section 10.2 Systems of Linear Equations: Matrices - 10.2 Assess Your Understanding - Page 752: 94
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