Answer
center $(1,-2)$, radius $r=4$,
see graph.
Work Step by Step
Form squares, we have
$x^2-2x+y^2+4y=11$,
$x^2-2x+1+y^2+4y+4=11+1+4$,
$(x-1)^2+(y+2)^2=16$,
thus we have the center $(1,-2)$, radius $r=4$,
see graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 10 - Systems of Equations and Inequalities - Cumulative Review - Page 817: 8
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