Answer
$(1,2),(3,4)$
Work Step by Step
1. From the 2nd equation we get $y=x+1$, plugin the 1st to get $2(x+1)^2-3x^2=5$ or $x^2-4x+3=0$ or $(x-3)(x-1)=0$, thus $$x=1,3$
2. For $x=3$, we have $y=4$
3. For $x=1$, we have $y=2$
4. The solutions are $(1,2),(3,4)$