Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.1 Functions - 1.1 Assess Your Understanding - Page 55: 85



Work Step by Step

It is given, that $f(0)=2$. Substituting $x=0$ into the function $f(x)$ gives: $f(x)=\dfrac{3(0)+8}{2(0)-A}$ $2=\dfrac{8}{-A}$ Solving this equation for $A$ gives: $\frac{8}{-A}=2$ $8=2(-A)\\ 8=-2A$ $-4=A$
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