## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$A=-4$
It is given, that $f(0)=2$. Substituting $x=0$ into the function $f(x)$ gives: $f(x)=\dfrac{3(0)+8}{2(0)-A}$ $2=\dfrac{8}{-A}$ Solving this equation for $A$ gives: $\frac{8}{-A}=2$ $8=2(-A)\\ 8=-2A$ $-4=A$