Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.1 Functions - 1.1 Assess Your Understanding - Page 53: 2

Answer

$22.5$

Work Step by Step

Substitute $-2$ to $x$ to obtain: \begin{align*} 3(-2)^2-5(-2)+\dfrac{1}{-2}&=3(-2)^2-5)(-2)+\dfrac{1}{-2}\\ &=3(4)+10-0.5\\ &=12+10-0.5\\ &=22-0.5\\ &=21.5 \end{align*}
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