Answer
$x^4-16.$
Work Step by Step
Since $(x^2-4)(x^2+4)$ is a factorization of the difference of two squares, then we have
$$
(x^2-4)(x^2+4)=x^4-16.
$$
Where we used the fact that
$a^2-b^2=(a+b)(a-b)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 2
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