## Precalculus (6th Edition)

$\color{blue}{\dfrac{\sqrt{7}}{6}}$
RECALL: For $a\gt0$ and $b\gt0$, $\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}$ Use the rule above to obtain: $=\dfrac{\sqrt{7}}{\sqrt{36}} \\=\dfrac{\sqrt{7}}{\sqrt{6^2}}$ Since $\sqrt{6^2}=6$, then the expression above simplifies to $=\color{blue}{\dfrac{\sqrt{7}}{6}}$