Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 62: 5


False Correct Statement: $(x+y)^{-1} = \dfrac{1}{x+y}$

Work Step by Step

RECALL: $a^{-m} = \dfrac{1}{a^m}$ Use the rule above to obtain: $(x+y)^{-1} = \dfrac{1}{(x+y)^1}=\dfrac{1}{x+y}$ Thus, the given statement is false. The correct statement is: $(x+y)^{-1} = \dfrac{1}{x+y}$
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