Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 52: 5


$\color{blue}{\dfrac{4}{x}} $

Work Step by Step

Cancel the common factors first before performing the actual multiplication to obtain: $\require{cancel} =\dfrac{2x}{5} \cdot \dfrac{2(5)}{x(x)} \\=\dfrac{2\cancel{x}}{\cancel{5}} \cdot \dfrac{2(\cancel{5})}{x\cancel{(x)}} \\=\dfrac{2}{1} \cdot \dfrac{2}{x} \\=\color{blue}{\dfrac{4}{x}} $
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