Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 45: 119



Work Step by Step

With $\frac{25}{9}x^4=(\frac{5}{3}x^2)^2$ and $9y^=(3y)^2$, the given binomial is equivalent to: $=(\frac{5}{3}x^2)^2-(3y)^2$ Factor using the formula $a^2-b^2=(a+b)(a-b)$ with $a=\frac{5}{3}x^2$ and $b=3y$ to obtain: $=\color{blue}{(\frac{5}{3}x^2+3y)(\frac{5}{3}x^2-3y)}$
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