Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 20: 48



Work Step by Step

If $p=-4$, $q=8$ and $r=-10$, then by substituting in the given expression, we get: $\frac{5q+2(1+p)^3}{r+3}=\frac{5(8)+2(1+(-4))^3}{(-10)+3}=\frac{40+2(-3)^3}{-7}=\frac{40+2(-27)}{-7}=\frac{-14}{-7}=2$
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