Answer
$\left\{-\sqrt{3}, 2\pi, \sqrt{12}\right\}$
Work Step by Step
RECALL:
Irrational numbers are numbers that cannot be expressed as a quotient of two integers a and b, where $b\ne0$.
Note that $-\sqrt3$, $2\pi$, and $\sqrt{12}$ cannot be expressed as $\dfrac{a}{b}$ where $a$ and $b$ are integers and $b\ne0$.
Thus, the elements of $A$ that are elements of the set of irrational numbers are:
$\left\{-\sqrt{3}, 2\pi, \sqrt{12}\right\}$
