## Precalculus (6th Edition)

RECALL: $A \subseteq B$ if all elements of $A$ are also elements of $B$ The elements of $E$ are: $3, 7$ The elements of $A$ are: $1, 3, 4, 5, 7, 8$ Since both elements of $E$ are also elements of $A$, then $E \subseteq A$ . Thus, the given statement is false.