Answer
$\{(-2,1,2)\}$
Work Step by Step
Use elimination:
1. Add up the first two equations to get $2y+2z=6$ or $y+z=3$
2. Multiply the above equation with $-1$ and add the result to the third equation to get $z=2$
3. Back-substitute to the third equation to get $y=5-2(2)=1$
4. Back-substitute the results to the first equation to get $x+1+2=1$ and $x=-2$
5. Thus the solution set is $\{(-2,1,2)\}$
