Answer
$\{(5,-1,0)\}$
Work Step by Step
The given first equation can be re-written as:
$y=5x-26~~~(1) $
Now, the given second equation can be re-written as: $4(5x-26)+3z=-4 \implies 20x +3z=100 ~~~~(2)$
Multiply equation (3) by -1 then add to eq-1 to obtain: $x=5$
Plug $x=5$ in first equation to obtain:
$5(5)-y=26 \implies y=-1$
Back substitution for $x=5$ and $y=-1$ to solve for $z$: $(3)(5)+(3)(z)=15 \implies z=0$
Solution set: $\{(5,-1,0)\}$
