Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.8 Matrix Inverses - 9.8 Exercises - Page 942: 9

Answer

The given matrices are inverse of each other.

Work Step by Step

When two matrices are the inverses of each other, then their products must be the identity matrix. Suppose that matrix- A and matrix-B are having size of $n \times n$ matrix form, then both are inverse of each other when either $AB=I_n$ or $BA=I_n$. We have $A=\begin{bmatrix} 5 & 7 \\ 2&3 \end{bmatrix}$ and $B=\begin{bmatrix} 3 & -7 \\ -2& 5 \end{bmatrix}$ . Now, $AB=\begin{bmatrix} 5 & 7 \\ 2&3 \end{bmatrix} \begin{bmatrix} 3 & -7 \\ -2& 5 \end{bmatrix} \\=\begin{bmatrix} 15-14 & -35+35 \\ 6-6&-14+15 \end{bmatrix} \\=\begin{bmatrix} 1 & 0 \\ 0&1 \end{bmatrix}$ This shows that $AB=I_2$, and the given matrices are inverse of each other.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.