Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.7 Properties of Matrices - 9.7 Exercises - Page 929: 37

Answer

$\left[\begin{array}{ll} -\sqrt{3} & -13\\ 4 & -2\sqrt{5}\\ -1 & -\sqrt{2} \end{array}\right]$

Work Step by Step

1. Check if the matrices have the same dimension. If they don't, the sum/difference is not defined. 2. The sum/difference will be a matrix with the same dimension. 3. Position by position, add/subtract the corresponding entries. --- $\left[\begin{array}{ll} \sqrt{3} & -4\\ 2 & -\sqrt{5}\\ -8 & \sqrt{8} \end{array}\right]-\left[\begin{array}{ll} 2\sqrt{3} & 9\\ -2 & \sqrt{5}\\ -7 & 3\sqrt{2} \end{array}\right]=$ ... dimensions match, continue $=\left[\begin{array}{ll} \sqrt{3}-2\sqrt{3} & -4-9\\ 2-(-2) & -\sqrt{5}-\sqrt{5}\\ -8-(-7) & \sqrt{8}-3\sqrt{2} \end{array}\right]$ $=\left[\begin{array}{ll} -\sqrt{3} & -13\\ 4 & -2\sqrt{5}\\ -1 & 2\sqrt{2}-3\sqrt{2} \end{array}\right]$ $=\left[\begin{array}{ll} -\sqrt{3} & -13\\ 4 & -2\sqrt{5}\\ -1 & -\sqrt{2} \end{array}\right]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.