Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.5 Nonlinear Systems of Equations - 9.5 Exercises - Page 903: 11

Answer

$${\text{The specified points are solution of the nonlinear system of equations}}$$

Work Step by Step

$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,y = 3{x^2}\,\,\,\left( {\bf{1}} \right) \cr & {x^2} + {y^2} = 10\,\,\,\,\,\left( {\bf{2}} \right) \cr & {\text{From the graph we have the solutions }}\left( { - 1,3} \right){\text{ and }}\left( {1,3} \right) \cr & \cr & {\text{Evaluate the point }}\left( { - 1,3} \right){\text{ for both equations}} \cr & y = 3{x^2} \to 3 = 3{\left( { - 1} \right)^2} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3 = 3 \cr & {x^2} + {y^2} = 10 \to {\left( { - 1} \right)^2} + {\left( 3 \right)^2} = 10 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,10 = 10 \cr & ,{\text{then the point }}\left( { - 1,3} \right){\text{ is a solution of the nonlinear sysyem}} \cr & \cr & {\text{Evaluate the point }}\left( {1,3} \right){\text{ for both equations}} \cr & y = 3{x^2} \to 3 = 3{\left( 1 \right)^2} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3 = 3 \cr & {x^2} + {y^2} = 10 \to {\left( 1 \right)^2} + {\left( 3 \right)^2} = 10 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,10 = 10 \cr & ,{\text{then the point }}\left( {1,3} \right){\text{ is a solution of the nonlinear sysyem}} \cr} $$
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