Answer
$\left[\begin{array}{ll}
1 & -4\\
0 & 28
\end{array}\right]$
Work Step by Step
$\left[\begin{array}{ll}
1 & -4\\
7+1(-7) & 0+(-4)(-7)
\end{array}\right]=\left[\begin{array}{ll}
1 & -4\\
0 & 28
\end{array}\right]$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 9 - Systems and Matrices - 9.2 Matrix Solution of Linear Systems - 9.2 Exercises - Page 870: 8
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